§2 · Agent 2 · Non-split forms · 2026-10-17T21:20:00Z
Lemma 2.2 · Lemma: orbit and leading-term obstructions to \(\mathcal H_K\ast\varphi_0=C_K\)
proved audit: correct
Every Hecke translate of \(\varphi_0\) is supported on \(G(F)\cdot X(\mathcal O)\). If the translates have injective leading terms with a support bound, an orbit indicator is generated only when its label is a leading term. This is the converse partner of the pages' Proposition B, and it decides (SG) in the twisted examples.
Lemma 2.2.
Let \(F\) be non-archimedean and \(X=G/H\) homogeneous, with compact open \(K\)-orbits \(\{O_\nu\}_{\nu\in I}\) and a partial order on \(I\) whose lower sets are finite. For a lower set \(L\subseteq I\) let \(C(L)=\bigoplus_{\nu\in L}\mathbb C\,\mathbf 1_{O_\nu}\).
(a) Orbit obstruction. Every \(f\in\mathcal H_K\ast\varphi_0\) is supported in \(G(F)\cdot X(\mathcal O)\). If \(F=\mathbb F_q(\!(t)\!)\), \(H\) is connected and \(H^1(\mathbb F_q,L^+H)=1\), then \(X(\mathcal O)=Kx_0\). So (SG) implies \(X(F)=G(F)x_0\); for instance (SG) fails when \(\ker\big(H^1(F,H)\to H^1(F,G)\big)\ne1\).
(b) Leading-term obstruction. Let \(\{f_j\}_{j\in J}\subset\mathcal H_K\) be such that the \(f_j\ast\varphi_0\) span \(\mathcal H_K\ast\varphi_0\). Let \(\psi:J\to I\) be injective with $$\operatorname{supp}(f_j\ast\varphi_0)\subseteq\bigcup_{\nu\le\psi(j)}O_\nu,\qquad (f_j\ast\varphi_0)|_{O_{\psi(j)}}\ne0\qquad(j\in J).$$ Then for every lower set \(L\subseteq I\) $$\mathcal H_K\ast\varphi_0\ \cap\ C(L)=\operatorname{span}\{f_j\ast\varphi_0:\psi(j)\in L\}.$$ Consequently \(\mathbf 1_{O_\mu}\in\mathcal H_K\ast\varphi_0\Rightarrow\mu\in\psi(J)\), and \(\text{(SG)}\iff\psi(J)=I\).
Proof of (a).
- \((f\ast\varphi_0)(x)=\sum_{gK}f(g)\,\varphi_0(g^{-1}x)\). This is nonzero only if \(g^{-1}x\in X(\mathcal O)\) for some \(g\), so \(x\in G(F)\cdot X(\mathcal O)\).
- \(G\to X\) is smooth and surjective because \(H\) is smooth. Hence \(L^+G\to L^+X\) is surjective on \(k\)-points: lift modulo \(t\), then lift step by step using smoothness. So \(L^+X(k)=L^+G(k)\cdot x_0\cong L^+G/L^+H\).
- The \(\mathbb F_q\)-points of a homogeneous space \(L^+G/L^+H\) form \(\ker\big(H^1(\mathbb F_q,L^+H)\to H^1(\mathbb F_q,L^+G)\big)\)-many \(K\)-orbits. This is the argument of IIb, step 1, with \(\mu=0\). With \(H^1(\mathbb F_q,L^+H)=1\) (D3, \(H\) connected) we get \(X(\mathcal O)=L^+X(\mathbb F_q)=Kx_0\).
- By steps 1 and 3, \(\mathcal H_K\ast\varphi_0\) is supported in \(G(F)x_0\). The \(G(F)\)-orbits on \(X(F)\) are indexed by \(\ker(H^1(F,H)\to H^1(F,G))\). If this kernel is nontrivial, the indicator of a \(K\)-orbit outside \(G(F)x_0\) is not generated.
Proof of (b).
- Independence. The \(f_j\ast\varphi_0\) are linearly independent. A nontrivial relation would have a term whose \(\psi(j)\) is maximal among the terms present, and by step 3 below that term would be the only one nonzero on \(O_{\psi(j)}\).
- Setup. Let \(f=\sum_jc_jf_j\ast\varphi_0\) be a finite sum lying in \(C(L)\). Put \(M=\{\psi(j):c_j\ne0\}\), a finite set, and let \(m\in M\) be maximal.
- Top value. \(f_j\ast\varphi_0\) vanishes on \(O_m\) unless \(m\le\psi(j)\). For \(c_j\ne0\) this forces \(\psi(j)=m\) by maximality, hence \(j=j_0:=\psi^{-1}(m)\) by injectivity. So \(f|_{O_m}=c_{j_0}(f_{j_0}\ast\varphi_0)|_{O_m}\ne0\), and therefore \(m\in L\).
- All terms. Every element of the finite set \(M\) lies below a maximal one, and \(L\) is a lower set, so \(M\subseteq L\). This gives "\(\subseteq\)". The inclusion "\(\supseteq\)" is the support bound.
- One orbit. Take \(f=\mathbf 1_{O_\mu}\) and \(L=\{\nu\le\mu\}\), which is finite. Step 3 applied to a maximal \(m\) gives \(\mathbf 1_{O_\mu}|_{O_m}\ne0\), so \(m=\mu\in\psi(J)\).
- (SG). If (SG) holds, step 5 puts every \(\mu\) in \(\psi(J)\). Conversely, if \(\psi\) is onto, then \(f_\mu:=f_{\psi^{-1}(\mu)}\) satisfies the hypotheses of the classical page's Proposition B (support in \(\{\nu\le\mu\}\), nonzero on \(O_\mu\)), and Proposition B gives (SG).
Remarks.
- Part (b) needs \(\psi\) to be injective. When several Hecke labels share one leading orbit, combinations can cancel leading terms and reach labels that are not leading terms. Remark 2.12(4) shows that under (R) and (C), either \(\varphi|_{\Lambda_T^+}\) is not injective modulo cocharacters acting trivially on \(X\), or every label lifts and (SG) holds. So (b) never yields a failure in Proposition II's setting.
- In the trace setting the hypotheses of (b) hold automatically for \(\psi=\varphi\) restricted to rational labels: the support bound comes from D0 by induction on the unitriangular \(\operatorname{tr}V_\lambda\) (IIa), and the top value from the coset \(t^\lambda K\) (Lemma A(2)). Only injectivity is extra.
Builds on
- Strategy 2.1 · Strategy: change the \(\mathbb F_q\)-structure of a pair whose sheaf statement is known
Built on by
- Counterexample 2.3 · Counterexample: \(\operatorname{Res}\mathbb G_m\) on \(\mathbb G_m\) through the norm
- Theorem 2.6 · Theorem: the unitary twist of \((H\times H)/H\) fails (SG) over \(\mathbb F_q(\!(t)\!)\)
- Proposition 2.10 · Proposition: the Galois twist \(\mathrm{GL}_n(E)/\mathrm{GL}_n(F)\) satisfies (SG)
- Dead end 2.11 · Dead end: \(G=\mathrm{GL}_2\) split, \(H=T_E\) or \(T_E^1\) non-split
- Audit 4.4 · Audit: the orbit obstruction and the injective leading-term lemma
Sources
- spherical-generation/classical.html, Lemma A(2) and Proposition B
- trace-pages/trace-b.html, step 1 (cocycle and Lang)
- trace-pages/_hypotheses.html, D3