§2 · Agent 2 · Non-split forms · 2026-10-17T21:25:57Z
Remark 2.12 · Remark: why the trace misses thick generation, and what (R) removes
proved audit: minor defect
Thick generation is a statement about the essential image of \(V\mapsto V\ast\mathrm{IC}_0\) up to retracts. (SG) is the span of traces of Weil objects of the Satake category. Three Frobenius effects separate the two. A leading-term condition forces failure. Under (R) and (C) that condition can never hold, and counterexamples are confined to uncovered labels.
Remark 2.12.
- (Proved) Two statements. (SG)\(_n\) holds iff the traces \(\operatorname{tr}_n(V\ast\mathrm{IC}_0,\beta\ast\mathrm{can})\), over Weil objects \((V,\beta)\) of \(\mathrm{Sat}_{G_k}\), span \(C_{K_n}\otimes\overline{\mathbb Q}_\ell\) (IIa, Lemma 2.8). \(\mathcal C_k^{\mathrm{Sat}}=\mathcal C_k\) holds iff every \(\mathrm{IC}_\nu\) is a retract of a shift of some \(V_\lambda\ast\mathrm{IC}_0\), \(\lambda\in\Lambda_T^+\) (Proposition I). The two differ by three Frobenius effects:
- (G1) retracts of \(V_\lambda\ast\mathrm{IC}_0\) with \(\sigma\lambda\ne\lambda\), whose Weil structures come from no Satake object and which are invisible at \(n=1\) (Counterexample 2.3, Lemma 2.8);
- (G2) for \(\sigma\lambda=\lambda\), cancellation in \(\operatorname{tr}A_{\nu,i}(\lambda)\), or linear dependence among the rational columns (Computation 2.9 has dependence with every row nonzero);
- (G3) Frobenius on orbit labels, which removes orbits from \(C_K\) and never adds obligations (Counterexample 2.3(3), Proposition 2.10).
- (Proved) Forcing criterion. Assume D0, D3, connected stabilizers, and a rational point on every Frobenius-stable orbit. If \(\varphi\) is injective on \((\Lambda_T^+)^\sigma\) (modulo elements acting trivially on \(X\)) and \(\varphi((\Lambda_T^+)^\sigma)\ne(\Lambda_S^+)^{\mathrm{Fr}}\), then (SG) fails. If moreover \(\mathcal M=\Lambda_S^+\) over \(k\), the pair is a counterexample to IId. Unitary twists are of this kind: \(\ker\varphi=X_*(T)^\theta=\{(a,-a)\}\) meets \(X_*(T)^\sigma=\{(a,a)\}\) only in \(0\).
- (Proved) Not an invariant of \((G_k,X_k)\). (SG) over \(\mathbb F_q(\!(t)\!)\) is not a function of \((G_k,X_k)\) (Proposition 2.10).
- (Proved, using the run's Lemma 4.8) Under (R) and (C).
- \(\sigma=1\) on \(\Lambda_T\) and every \(\mathcal O_\mu\) has the rational point \(x_\mu\), so (G1) and (G3) are void.
- \(\varphi\) is never injective on \(\Lambda_T^+\) itself in rank \(\ge1\). If it is injective modulo cocharacters acting trivially on \(X\), then (C) forces every label to lift, so (SG) holds. Either way the criterion of item 2 never produces a failure.
- If every \(\mu\in\Lambda_S^+\) lies in \(\varphi(\Lambda_T^+)\), (SG) holds over \(\mathbb F_q(\!(t)\!)\) (verdict, Theorem 4, last sentence, Lemma 4.8 of the run).
- (Heuristic) Categorical trace. Once \(\mathcal C_k^{\mathrm{Sat}}=\mathcal C_k\), \(\mathrm{Tr}(\mathrm{Fr},\mathcal C_k^{\mathrm{Sat}})=\mathrm{Tr}(\mathrm{Fr},\mathcal C_k)\) tautologically, and it contains every class \([\mathrm{IC}_\nu,\mathrm{can}]\). (SG) concerns instead the image of \(\mathrm{Tr}(\mathrm{Fr},\mathrm{Sat}_{G_k})\) under the action functor \(a(V)=V\ast\mathrm{IC}_0\), which is not full. For example \(\operatorname{Hom}_{\mathrm{Sat}}(V_{(c,0)},\mathrm{Fr}^*V_{(c,0)})=0\), while \(\operatorname{Hom}_{\mathcal C_k}(\mathrm{IC}_c,\mathrm{Fr}^*\mathrm{IC}_c)\ni\mathrm{can}\).
1. Two statements. The first equivalence is IIa together with Lemma 2.8(2)–(3). The second is Proposition I. (G1) is Lemma 2.8(3)–(4): the summand \(\mathrm{IC}_c=V_{(c,0)}\ast\mathrm{IC}_0\) carries Weil structures, but only induced Weil objects of \(\mathrm{Sat}\) contribute to \(\mathcal H_K\ast\varphi_0\), and those see \(V_{(c,0)}\oplus V_{(0,c)}\) with an off-diagonal Frobenius. For (G3), a non-stable orbit has no rational points, so it does not index a \(K\)-orbit.
2. Forcing criterion.
- Support. \(\operatorname{tr}V_\lambda=\pm T_\lambda+\sum_{\mu<\lambda}a_{\lambda\mu}T_\mu\) for rational \(\lambda\), and \(\operatorname{supp}(V_\lambda\ast\mathrm{IC}_0)\subseteq\overline{\mathcal O_{\varphi(\lambda)}}\) (D0). Induction on \(\lambda\), using that \(\varphi\) is order-preserving, gives \(\operatorname{supp}(T_\lambda\ast\varphi_0)\subseteq\bigcup_{\nu\le\varphi(\lambda)}O_\nu\).
- Top value. \(t^\lambda x_0\in\mathcal O_{\varphi(\lambda)}(\mathbb F_q)\) gives \((T_\lambda\ast\varphi_0)(t^\lambda x_0)\ge1\) (Lemma A(2)).
- Conclusion. Lemma 2.2(b) with \(\psi=\varphi|_{(\Lambda_T^+)^\sigma}\) shows that the labels outside \(\varphi((\Lambda_T^+)^\sigma)\) are not generated.
- Unitary twist. \(\theta(a,b)=(-b,-a)\) and \(\sigma(a,b)=(b,a)\) give \(\varphi(a,a)=(2a,2a)\), injective, with image \(2\Lambda_H^+\ne\Lambda_H^+\).
4. Under (R) and (C).
- (R) makes \(T\) split, so \(\sigma=1\), and \(S\) split, so \(t^\mu\in S(F)\) and every orbit is Frobenius-stable with a rational point.
- Injectivity on \(\Lambda_T^+\). A nonzero \(\kappa\in\ker\varphi=X_*(T)^\theta\) gives \(\varphi(N\xi+\kappa)=\varphi(N\xi)\), with both arguments dominant for \(\xi\) regular dominant and \(N\gg0\). So injectivity on \(\Lambda_T^+\) forces \(X_*(T)^\theta=0\), hence \(T=S\), \(Z_G(S)=T\) and \(Z_{G^\theta}(S)=T[2]\cong\mu_2^{\operatorname{rk}G}\), which is disconnected for \(p\) odd and rank \(\ge1\). Under (C), then, \(\varphi\) is never injective on \(\Lambda_T^+\).
- Injectivity modulo trivially acting cocharacters. Since \(T_\lambda\) and \(T_{\lambda+\kappa}\) act identically on \(C_K\) when \(t^\kappa\) acts trivially on \(X\), the relevant condition is injectivity modulo such \(\kappa\). By the same \(N\xi+\kappa\) argument, it forces every \(\kappa\in X_*(T)^\theta\) to act trivially on \(X\) after passing to a multiple, so \(Z':=(T^\theta)^\circ\) acts trivially on \(X\). Divide \(G\) by any simple factor that acts trivially on \(X\); such a factor only rescales Hecke operators by their degrees. The kernel of the action is then a normal subgroup whose identity component is a central torus, so \(Z'\) is central in \(G\). Every root is nonzero on \(S\), since a root vanishing on \(S\) would vanish on \(SZ'=T\); hence \(Z_G(S)=T\) and \(T=S\cdot Z'\).
- Consider \(f:T\to S\), \(t\mapsto t\theta(t)^{-1}\). It is surjective (\(f(s)=s^2\) on \(S\)) with kernel \(T^\theta=Z_{G^\theta}(S)\), and \(X_*(f)=\varphi\). The cokernel of \(X_*(f)\) has order \(|\pi_0(\ker f)|\), so under (C) \(\varphi:\Lambda_T\to\Lambda_S\) is onto.
- A preimage \(\lambda=\tfrac12\mu+\zeta\), \(\zeta\in X_*(Z')_{\mathbb Q}\), of a dominant \(\mu\) is dominant, because roots vanish on the central \(Z'\).
- So every label lifts dominantly, and (SG) holds by Lemma 4.8 of the run. The forcing criterion yields nothing under (R) and (C), and a failure there must come from cancellations among Hecke operators sharing a leading orbit.
- The positive statement is the run's Lemma 4.8, quoted in the verdict: split symmetric spaces meeting Proposition III's two conditions (connected \(Z_{G^\theta}(S)\) and dominant lifts) satisfy (SG) over \(\mathbb F_q(\!(t)\!)\) under D0, D3.
5. Categorical trace. This item is heuristic; no statement of AGKRRV or Zhu on categorical traces is used or checked here. On the level of trace functions, the precise content is Lemma 2.8(4). In \(\mathrm{HH}_0(\mathcal C,\mathrm{Fr}^*)\), a retract \(M\xrightarrow{i}N\xrightarrow{p}M\) satisfies \([M,\beta]=[N,\mathrm{Fr}^*(i)\circ\beta\circ p]\) by cyclicity. The map \(\mathrm{Fr}^*(i)\beta p\) is a morphism of \(\mathcal C_k\) that need not come from \(\mathrm{Sat}\). Thick closure therefore enlarges the trace by exactly such classes, while (SG) uses only the classes coming from \(\mathrm{Sat}\).
Builds on
- Counterexample 2.3 · Counterexample: \(\operatorname{Res}\mathbb G_m\) on \(\mathbb G_m\) through the norm
- Theorem 2.6 · Theorem: the unitary twist of \((H\times H)/H\) fails (SG) over \(\mathbb F_q(\!(t)\!)\)
- Lemma 2.8 · Lemma: Satake objects without a Weil structure are invisible to the trace at \(n=1\)
- Computation 2.9 · Computation: unitary \(\mathrm{SL}_2\): every row of \(m^{(1)}\) nonzero, no spanning
- Proposition 2.10 · Proposition: the Galois twist \(\mathrm{GL}_n(E)/\mathrm{GL}_n(F)\) satisfies (SG)
- Dead end 2.11 · Dead end: \(G=\mathrm{GL}_2\) split, \(H=T_E\) or \(T_E^1\) non-split
Built on by
- Summary 2.13 · Verdict: sheaves do not imply (SG) when \(T\) is non-split; nothing new under (R)
- Audit 4.19 · Audit: under (R), (C), injective leading terms force dominant lifts
- Theorem 6.3 · Verdict: sheaf generation over \(\overline{\mathbb F}_q\) does not imply spherical generation over \(\mathbb F_q(\!(t)\!)\)
Sources
- satake-two-levels/verdict.html, Theorem 4 (Lemma 4.8 of the run) and §7
- trace-pages/trace.html, Limits
- spherical-generation/classical.html, Corollary C, Lemma A(2)
- trace-pages/_definitions.html, Proposition I